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91.8^2+24.6^2=c^2
We move all terms to the left:
91.8^2+24.6^2-(c^2)=0
We add all the numbers together, and all the variables
-1c^2+9032.4=0
a = -1; b = 0; c = +9032.4;
Δ = b2-4ac
Δ = 02-4·(-1)·9032.4
Δ = 36129.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{36129.6}}{2*-1}=\frac{0-\sqrt{36129.6}}{-2} =-\frac{\sqrt{}}{-2} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{36129.6}}{2*-1}=\frac{0+\sqrt{36129.6}}{-2} =\frac{\sqrt{}}{-2} $
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